| |
Wed 19-Sep-2007 00:9:20
| Name : CHEW JIE YING | |||
| Admission Number : 072537P | |||
| Course : DIPLOMA IN FOOD SCIENCE (CLDF03) | |||
| Please refer below to find out how to compute your Grade Point Average (GPA): | |||
| Module Code | Module Description | Module Credit | Module Grade | Grade Point | Module Credit Earned | Grade Point x Module Credit Earned |
| CL1101 | PHYSICAL CHEMISTRY | 4 | D+ | 1.5 | 4 | 6.0 |
| CL1102 | INORGANIC CHEMISTRY | 4 | D+ | 1.5 | 4 | 6.0 |
| CL1104 | MATHEMATICS FOR LIFE SCIENCE | 3 | C+ | 2.5 | 3 | 7.5 |
| CL1501 | MICROBIOLOGY FOR FOOD SCIENCES | 5 | D+ | 1.5 | 5 | 7.5 |
| CL1502 | PRINCIPLES OF ECONOMICS | 3 | D | 1.0 | 3 | 3.0 |
| CL1505 | INTRODUCTION TO FOOD SCIENCE | 5 | D | 1.0 | 5 | 5.0 |
| CL9201 | GERMAN | 4 | C | 2.0 | 4 | 8.0 |
| Total: | 28 | 43.0 |
| Total Grade Points x Module Credits Earned = 43.0 |
| Total Module Credits = 28 |
| GPA = ∑(Grade Point x Module Credit Earned) / ∑(Module Credit) |
| Hence, your GPA is 43.0/28 = 1.536 |
| Grade-to-Point Conversion |
| Module Grade | | | Grade Point |
| DIST | : | Distinction (Awarded by the Assessment Board) | 4.0 |
| A | : | >=80% | 4.0 |
| B+ | : | 75%-<80%> | 3.5 |
| B | : | 70%-<75%> | 3.0 |
| C+ | : | 65%-<70%> | 2.5 |
| C | : | 60%-<65%> | 2.0 |
| D+ | : | 55%-<60%> | 1.5 |
| D | : | 50%-<55%> | 1.0 |
| F | : | <50%> | 0.0 |
| P | : | Pass (for modules graded Pass/Fail) | NA |
| SP | : | Supplementary Pass | 1.0 |
| SF | : | Supplementary Fail | 0.0 |
| *AUD | : | Met attendance requirement but, where permitted, did not sit for exams | NA |
| *DEB | : | Debarred | 0.0 |
| *DEF | : | Grading deferred to a later date for acceptable reasons | NA |
| *TRF | : | Credits Transferred | NA |
| *WDC | : | Withdrawn from Course | NA |
| *WDM | : | Withdrawn Subject / Module | NA |
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